This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1101110112 = 110 111 011 = 110(=6) 111(=7) 011(=3) = 6738
answer: 1101110112 = 6738
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20 = 1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1 = 256+128+0+32+16+8+0+2+1 = 44310
got It: 1101110112 =44310
Translate the number 44310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
| 443 | 8 | | |
| -440 | 55 | 8 | |
| 3 | -48 | 6 | |
| 7 | | |
 |
the result of the conversion was:
44310 = 6738
answer: 1101110112 = 6738