This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙160+0∙16-1+0∙16-2+1∙16-3+1∙16-4+1∙16-5 = 1∙1+0∙0.0625+0∙0.00390625+1∙0.000244140625+1∙1.52587890625E-5+1∙9.5367431640625E-7 = 1+0+0+0.000244140625+1.52587890625E-5+9.5367431640625E-7 = 1.0002603530883789110
got It: 1.0011116 =1.0002603530883789110
Translate the number 1.0002603530883789110 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
 |
| 0. | 00026035308837891*8 |
| 0 | .00208*8 |
| 0 | .01666*8 |
| 0 | .1333*8 |
| 1 | .06641*8 |
| 0 | .53125*8 |
| 4 | .25*8 |
| 2 | .0*8 |
| 6 | .0*8 |
the result of the conversion was:
1.0002603530883789110 = 1.000104268
answer: 1.0011116 = 1.000104268
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
1.0011116 = 1. 0 0 1 1 1 = 1(=0001). 0(=0000) 0(=0000) 1(=0001) 1(=0001) 1(=0001) = 1.000000000001000100012
answer: 1.0011116 = 1.000000000001000100012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001.0000000000010001000102 = 001. 000 000 000 001 000 100 010 = 001(=1). 000(=0) 000(=0) 000(=0) 001(=1) 000(=0) 100(=4) 010(=2) = 1.00010428
answer: 1.0011116 = 1.00010428