This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from binary to hexadecimal like this:
1110011111001001_{2} = 1110 0111 1100 1001 = 1110_{(=E)} 0111_{(=7)} 1100_{(=C)} 1001_{(=9)} = E7C9_{16}
the Final answer: 1110011111001001_{2} = E7C9_{16}
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙2^{15}+1∙2^{14}+1∙2^{13}+0∙2^{12}+0∙2^{11}+1∙2^{10}+1∙2^{9}+1∙2^{8}+1∙2^{7}+1∙2^{6}+0∙2^{5}+0∙2^{4}+1∙2^{3}+0∙2^{2}+0∙2^{1}+1∙2^{0} = 1∙32768+1∙16384+1∙8192+0∙4096+0∙2048+1∙1024+1∙512+1∙256+1∙128+1∙64+0∙32+0∙16+1∙8+0∙4+0∙2+1∙1 = 32768+16384+8192+0+0+1024+512+256+128+64+0+0+8+0+0+1 = 59337_{10}
got It: 1110011111001001_{2} =59337_{10}
Translate the number 59337_{10} в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
59337  16    
59328  3708  16   
9  3696  231  16  
 C  224  E  
  7   

the result of the conversion was:
59337_{10} = E7C9_{16}
the Final answer: 1110011111001001_{2} = E7C9_{16}